document.write( "Question 98604: Bob invested $20,000, part at 14% and part at 13%. If the total interest at teh end of the year is $2,720, how much did he invest at 14%?
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Algebra.Com's Answer #71746 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .14X+.13(20000-X)=2720. \n" ); document.write( ".14X+2600-.13X=2720 \n" ); document.write( ".14X-.13X=2720-2600 \n" ); document.write( ".01X=120 \n" ); document.write( "X=120/.01 \n" ); document.write( "X=12000 ANSWER INVESTED @ 14%. \n" ); document.write( "20000-12000=8000 INVESTED @ 13%. \n" ); document.write( "PROOF \n" ); document.write( ".14*12000+.13*8000=2720 \n" ); document.write( "1680+1040=2720 \n" ); document.write( "2720=2720 \n" ); document.write( " |