document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102643>Question 1102643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rain gutter  is made from sheets of aluminum that are 19 inches wide.  The edges are turned up to form right angles.  Determine the depth  of the gutter that will allow a cross-sectional area of 18 square inches.  Show that there are two different solutions to the problem .  Round to the nearest 10th of an inch  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717444 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width after turning up the edges will be w = 19 - 2h, where h is the height<BR>\n" );
document.write( "The cross-sectional area A = w*h = 18<BR>\n" );
document.write( "h(19-2h) = 18<BR>\n" );
document.write( "2h^2 - 19h + 18 = 0<BR>\n" );
document.write( "Using the quadratic formula, the two solutions are:<BR>\n" );
document.write( "h = 1.1 and 8.4<BR>\n" );
document.write( "Ans: 1.1 inches and 8.4 inches </SPAN>\n" );
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