document.write( "Question 1102688: The formula P=0.67x2–0.042x + 1 models the approximate population (P), in thousands, for a species of fish in a local pond, x years after 1997. During what year will the population reach 54,892 fish?\r
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\n" ); document.write( "\n" ); document.write( "I got about 2090 using the quadratic equation. However, the fact that I had to round to get a whole answer makes me think I got it wrong. Is it correct?
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Algebra.Com's Answer #717427 by greenestamps(13198)\"\" \"About 
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\n" ); document.write( "The other tutor overlooked the fact that the formula gives the number of fish in thousands, not the actual number of fish. Otherwise his method is a perfectly good way to get the answer.

\n" ); document.write( "\"0.67x%5E2-0.042x%2B1+=+54.892\"

\n" ); document.write( "For a quadratic equation with \"ugly\" coefficients like this, it's by far easiest to use a graphing calculator or some other tool to find the solution. I used my TI83 to graph the function and the constant to see where they intersect:

\n" ); document.write( "\"graph%28200%2C200%2C-2%2C12%2C-15%2C85%2C0.67x%5E2-0.042x%2B1%2C54.892%29\"

\n" ); document.write( "This is clearly a contrived problem, as the solution turns out to be exactly 9.

\n" ); document.write( "Since x is the number of years after 1997, the answer is 2006.
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