document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102641>Question 1102641</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the interest earned of a 12-year investment with an interest rate of 5.3% compounded weekly, if the Future value is $41800\r<BR>\n" );
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document.write( "A) 17 630.77 B) 356.07 C) 14 404.36 D) 19 663.67 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717371 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 41800=Po(1+.053/52)^624, since 624 weeks in 12 years (actually probably closer to 626, but shouldn't matter in answer.)<BR>\n" );
document.write( "Po=$22166.33<BR>\n" );
document.write( "subtract that from 41800 to get interest and get 19 633.67 <BR>\n" );
document.write( "D. </SPAN>\n" );
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