document.write( "Question 98603: 3-4q=10q+10 \n" ); document.write( "
Algebra.Com's Answer #71734 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"3-4q=10q%2B10\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"-4q=10q%2B10-3\"Subtract 3 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-4q-10q=10-3\" Subtract 10q from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-14q=10-3\" Combine like terms on the left side\r
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\n" ); document.write( "\n" ); document.write( "\"-14q=7\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"q=%287%29%2F%28-14%29\" Divide both sides by -14 to isolate q\r
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\n" ); document.write( "\n" ); document.write( "\"q=-1+%2F+2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So our answer is \"q=-1+%2F+2\" (which is \"q=-0.5\" in decimal form)
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