document.write( "Question 1102512: Determine the interest earned of a 12-year investment with an interest rate of 5.3 %/a compounded weekly, if future value is $41800. \r
\n" ); document.write( "\n" ); document.write( "A) $ 17 630.77 B) $ 356.07 C) $ 14404.36 D) $19 663.67
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Algebra.Com's Answer #717312 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "If the initial amount is A, then the amount after 12 years, compounded weekly (52 times a year), with an annual interest rate of 5.3%, is

\n" ); document.write( "\"A%281%2B%28.053%2F52%29%5E%2812%2A52%29%29+=+A%2A1.8883\"

\n" ); document.write( "Given that the future value is $41800, the original amount is
\n" ); document.write( "\"A%2A1.8883+=+41800\"
\n" ); document.write( "\"A+=+41800%2F1.8333+=+22136.33\"

\n" ); document.write( "The original amount is $22136.33; the future value is $41800; the interest is
\n" ); document.write( "\"41800-22136.33+=+19663.67\"

\n" ); document.write( "Answer D.

\n" ); document.write( "Note there is a faster way to get to the interest amount, after we find that
\n" ); document.write( "\"A%2A1.8883+=+41800\"

\n" ); document.write( "In that equation, A*1 is the original amount; A*0.8883 is the interest. So the fraction of the total future value of $41800 that is interest is 0.8883/1.8883. So the amount of interest is
\n" ); document.write( "\"41800%2A%280.8883%2F1.8883%29+=+19663.67\"
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