document.write( "Question 1102565: the length of a rectangle is 4 centimeters more than the width. If both the width and the length were tripled, the area would be 108 square centimeters. Find the dimensions of the orginal rectangle
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Algebra.Com's Answer #717310 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "When the length and width are both tripled (multiplied by 3), the area is increased by a factor of 3*3=9. So the original area was 108/9=12. \n" ); document.write( "Inspection shows that two numbers that differ by 4 and have a product of 12 are 2 and 6; those are the dimensions of the original rectangle. \n" ); document.write( "If you need the formal algebra, it might look like this.... \n" ); document.write( "let x = original width \n" ); document.write( "then x+4=original length \n" ); document.write( "3x = new width \n" ); document.write( "3(x+4) = 3x+12 = new length \n" ); document.write( "The new area (length times width) is 108: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x = -6 or x = 2; \n" ); document.write( "reject the negative solution since it is the width \n" ); document.write( "The original width was x=2; the original length was x+4=6. \n" ); document.write( "Learning how to solve the problem using formal algebra is good training, for when the problems get too complicated to solve informally by logical reasoning. \n" ); document.write( "But you should also be able to use your powers of logical reasoning to solve simpler problems like this, without formal mathematical methods. \n" ); document.write( " |