document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98496>Question 98496</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618386807/algebrahomeworkh>College Algebra and Trigonometry </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A radiator contains 6 liters of 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 33% antifreeze solution?\r<BR>\n" );
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document.write( "So far, I know that the first solution contains 6 liters and I need to multiply that by 25%. Then since we are \"replacing\" pure antifreeze to the mixture that is 100% that I need to multiply to the unknown mixture of x+6 (which is my second solution) so that I can produce a 33% solution. Does this make any sense? I'm not sure how to do this. Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71728 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A radiator contains 6 liters of 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 33% antifreeze solution? <BR>\n" );
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document.write( "Note: Keep track of the active ingredient.<BR>\n" );
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document.write( "Start: 25%*6 liters = (3/2)liters of active<BR>\n" );
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document.write( "You subtract x liters but it is still 25% active:<BR>\n" );
document.write( "You now have: (3/2)-(x/4) active;<BR>\n" );
document.write( "You add x amount of 100% active:<BR>\n" );
document.write( "You now have (3/2)-(x/4)+x active<BR>\n" );
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document.write( "That amount of active is 33% of the 6 liters you now have:<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "(3/2)-(x/4)+x = 33%*6<BR>\n" );
document.write( "(3/2) + (3/4)x = 2<BR>\n" );
document.write( "(3/4)x = 1/2<BR>\n" );
document.write( "x = (1/2)(4/3)<BR>\n" );
document.write( "x = 2/3 liters<BR>\n" );
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document.write( "That is the amount of 100% alcohol you should add.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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