document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98600>Question 98600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twice the reciprocal of a number is nine more than five times the number. find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71727 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2*1/X=9+5X<BR>\n" );
document.write( "2/X=9+5X NOW CROSS MULTIPLY<BR>\n" );
document.write( "9X+5X^2=2<BR>\n" );
document.write( "5X^2+9X-2=0<BR>\n" );
document.write( "(5X-1)(X+2)=0 <BR>\n" );
document.write( "-------------------------------------------------------------<BR>\n" );
document.write( "FOIL f=first 5x*x=5x^2, o=outer-1*2=-2 i=inner-1*x=-x & l=last=2+5x=10x now combine all these terms you get 5x^2+10x-x-2 or 5x^2+9x-2<BR>\n" );
document.write( "that's where the 9x went it became 10x-1x=9x.<BR>\n" );
document.write( "-----------------------------------------------------------------<BR>\n" );
document.write( "5X-1=0<BR>\n" );
document.write( "5X=1<BR>\n" );
document.write( "X=1/5 OR .2 ANSWER.<BR>\n" );
document.write( "X+2=0<BR>\n" );
document.write( "X-2 ANSWER.<BR>\n" );
document.write( "PROOFS:<BR>\n" );
document.write( "2*1/.2=9+5*.2<BR>\n" );
document.write( "2*5=9+1<BR>\n" );
document.write( "10=10<BR>\n" );
document.write( "2*1/-2=9+5*-2<BR>\n" );
document.write( "-1=9-10<BR>\n" );
document.write( "-1=-1<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );