document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102553>Question 1102553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need explanation how to solve this problem, thank you. I see some examples on the internet but there is no explanation how they get that result.\r<BR>\n" );
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document.write( "On the basis of data from 1990 to 2006, the median income y in year x for mean and women is approximated by the equations given below, where x=0 corresponds to 1990 and y is in constant 2006 dollars. If these equations remain valid in the future, when will with the median income of men and women be the same? \r<BR>\n" );
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document.write( "Men: -255x+2y=56,937<BR>\n" );
document.write( "Women: - 842x+3y=42,751<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717255 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717255\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Both are linear equations. Where they intersect is where they are equal<BR>\n" );
document.write( "-255x+2y=56,937<BR>\n" );
document.write( "- 842x+3y=42,751<BR>\n" );
document.write( "multiply top by -3 and bottom by 2 to eliminate y<BR>\n" );
document.write( "765x-6y=-170811<BR>\n" );
document.write( "-1684x+6y=85502 add them<BR>\n" );
document.write( "-919x=-85309 divide by -919 both sides<BR>\n" );
document.write( "x=92.83<BR>\n" );
document.write( "substitute into first equation to get y<BR>\n" );
document.write( "-23671.16+2y=56937<BR>\n" );
document.write( "2y=80608.16<BR>\n" );
document.write( "y=40304.08<BR>\n" );
document.write( "Check in second equation<BR>\n" );
document.write( "-842*92.83+3(40304.08)=42749.38, close enough with rounding.<BR>\n" );
document.write( "x=92.83 which will be in 2073.83 or well into that year.<BR>\n" );
document.write( "y=40304.08, which is what the income will be in constant 2006 dollars </SPAN>\n" );
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