document.write( "Question 1102520: The sum of non zero number an twice it's reciprocal is 33/4 find the number \n" ); document.write( "
Algebra.Com's Answer #717225 by Theo(13342)![]() ![]() You can put this solution on YOUR website! if x is the number, then the reciprocal of x is 1/x. \n" ); document.write( "2 times the reciprocal of x is 2/x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 2/x = 33/4 \n" ); document.write( "multiply both sides of this equation by 4x to get 4x^2 + 8 = 33x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 33x from both sides of this equation and re-order the terms in descending order of degree to get 4x^2 - 33x + 8 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor this quadratic equation to get(4x-1) * (x-8) = 0 \n" ); document.write( "solve for x to get x = 1/4 or x = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 1/4, the reciprocal of x is equal to 4 and 2 times the reciprocal of x is equal to 8. \n" ); document.write( "x + 2/x becomes 1/4 + 8 which becomes 1/4 + 32/4 which is equal to 33/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 8, the reciprocal of x is equal to 1/8 and 2 times the reciprocal of x is equal to 2/8 which is equal to 1/4. \n" ); document.write( "x + 2/x becomes 8 + 1/4 which becomes 32/4 + 1/4 which is equal to 33/4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "both solutions are good. \n" ); document.write( "the number can be 1/4 or 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |