document.write( "Question 1102502: A square piece of tin is made into an open box by cutting a 6 cm square from each corner. The volume of the box is 1536 cm^2. What was the area, in cm^2, of the original piece of tin? \n" ); document.write( "

Algebra.Com's Answer #717214 by ikleyn(52879) $\"\"$ $\"About$

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document.write( "    1.  The bottom area of the open box =  =  = 256 cm^2.\r\n" );
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document.write( "    2.  The side measure of the box bottom =  = 16 cm.\r\n" );
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document.write( "    3.  The side dimension of the original square piece of tin is 16 + 2*6 = 28 cm.\r\n" );
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document.write( "    4.  The area of the original piece of tin is 28^2 = 784 cm^2.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Answer. The area of the original piece of tin is 784 cm^2.\r
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\n" ); document.write( "Be aware !! The approach and the solution by @josgarithmetic are I N A D E Q U A T E AND I R R E L E V A N T !!\r
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