document.write( "Question 1102502: A square piece of tin is made into an open box by cutting a 6 cm square from each corner. The volume of the box is 1536 cm^2. What was the area, in cm^2, of the original piece of tin? \n" ); document.write( "
Algebra.Com's Answer #717213 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
Let x be the edge length of each square piece removed from a corner.\r
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\n" ); document.write( "\n" ); document.write( "volume of the open box: \"cross%28x%28x-2%2A6%29%5E2=1536%29\" \"6%28x%5E2-2%2A6%29%5E2=1536\"
\n" ); document.write( "\"6%28x-12%29%5E2=1536\"\r
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\n" ); document.write( "\n" ); document.write( "(.....), \"%28x-12%29%5E2=1536%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-12%29%5E2=highlight%28256%29\"------the area of the base.\r
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\n" ); document.write( "\n" ); document.write( "\"x-12=sqrt%28256%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x-12=16\"\r
\n" ); document.write( "\n" ); document.write( "\"x=16%2B12\"\r
\n" ); document.write( "\n" ); document.write( "\"x=28\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2=28%5E2=highlight_green%28784%29\"------area of original piece of tin\r
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