document.write( "Question 1102492: . Find the equation of the line passing through the point (3, 7) and
\n" ); document.write( "perpendicular to the line 3y = 4 – 2x \n" ); document.write( "

Algebra.Com's Answer #717205 by ikleyn(52814) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "Find the equation of the line passing through the point (3, 7) and
\n" ); document.write( "perpendicular to the line 3y = 4 – 2x
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "

\r\n" );
document.write( "The given line  y =  +  has the slope of .\r\n" );
document.write( "\r\n" );
document.write( "Since the projected/requested line is perpendicular to the given line, it has the slope value opposite to reciprocal, i.e. .\r\n" );
document.write( "\r\n" );
document.write( "Hence, the projected/requested line has an equation of the form  y =   with unknown coefficient \"b\".\r\n" );
document.write( "\r\n" );
document.write( "To find \"b\", simply substitute the coordinates of the given point x= 3 and y= 7 respectively into this equation  y = .  You will get\r\n" );
document.write( "\r\n" );
document.write( "7 = ,   or  14 = 3*3 + 2b,\r\n" );
document.write( "\r\n" );
document.write( "which implies  2b = 14 - 9 = 5  and  b = .\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Thus your final equation of the projected/requested straight line is \r\n" );
document.write( "\r\n" );
document.write( "y = ,  or  2y = 3x + 5.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );