document.write( "Question 1102493: Log 2 = 0.301 log 3 = 0.477 log 5 = 0.699 using this information
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document.write( "Find:- a) Log 6/5 b) Log 0.75 = \n" );
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Algebra.Com's Answer #717203 by Alan3354(69443) You can put this solution on YOUR website! Log 2 = 0.301 log 3 = 0.477 log 5 = 0.699 using this information \n" ); document.write( "Find:- a) Log 6/5 \n" ); document.write( "6/5 = 2*3/5 \n" ); document.write( "========= \n" ); document.write( " b) Log 0.75 = \n" ); document.write( "3/4 = 3/(2*2) \n" ); document.write( " |