document.write( "Question 1102481: Question 10
\n" ); document.write( "Jennifer Cantu, Vice President of Customer Services at Tri-State Auto Insurance Inc.,
\n" ); document.write( "monitors the claims processing time of the claims division. Each week, her staff randomly
\n" ); document.write( "selects a sample of 64 claims. They test the null hypothesis that the \"mean processing time
\n" ); document.write( "is 5 days\" and the alternative hypothesis that the \"mean processing time is more than 5
\n" ); document.write( "days\" using the 0.05 level of significance. Last week the sample mean was 5.2 days.
\n" ); document.write( "Assuming a population standard deviation of 1.56 days, the appropriate decision is _____.\r
\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "a.
\n" ); document.write( "reduce the sample size
\n" ); document.write( "b.
\n" ); document.write( "do not reject the null hypothesis
\n" ); document.write( "c.
\n" ); document.write( "increase the sample size
\n" ); document.write( "d.
\n" ); document.write( "reject the null hypothesis
\n" ); document.write( "
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Algebra.Com's Answer #717195 by Boreal(15235)\"\" \"About 
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At the 0.05 level of significance,
\n" ); document.write( "test statistic is z=(xbar-mean)/sigma/sqrt(n)=(5.2-5)/1.56/sqrt (64)
\n" ); document.write( "This is z=0.2*8/1.56=1.03. This has a p-value of 0.15 which is greater than alpha of 0.05, so fail to reject Ho and b. is the answer.\r
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\n" ); document.write( "\n" ); document.write( "If one uses a two-sided test, the 95% CI half interval is 1.96*1.56/8, z*sigma/sqrt(n), using a z test because the population sd is used. That half-interval is 0.38, so the 95% CI is [4.82, 5.58].
\n" ); document.write( "The appropriate decisions is b., do not reject Ho. The 95% CI contains the null hypothesis, and that means the null hypothesis is not rejected.
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