document.write( "Question 1102468: It is Khadijah’s birthday today. One year from now she will be twice as old as she was 10 years ago. Calculate the present age of Khadijah. \n" ); document.write( "
Algebra.Com's Answer #717164 by Theo(13342) You can put this solution on YOUR website! let x = the age of khadijah today. \n" ); document.write( "1 year from now, khadijah will be x + 1 years old. \n" ); document.write( "1 year from now, she will be twice as old as she was 10 years ago. \n" ); document.write( "10 years ago, she was x - 10 years old. \n" ); document.write( "your equation is x+1 = 2 * (x-10) \n" ); document.write( "simplify to get x+1 = 2x - 20 \n" ); document.write( "add 20 both sides and subtract x from both sides of this equation to get: \n" ); document.write( "21 = x \n" ); document.write( "that's the age of khadijah today. \n" ); document.write( "1 year from now she will be 22. \n" ); document.write( "10 years ago she was 11. \n" ); document.write( "22 is equal to 2 * 11. \n" ); document.write( "this confirms that 1 year from now she will be twice as old as she was 10 years ago.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |