document.write( "Question 1102443: Find the final amount of money in an account if $4,700 is deposited at 3% interest compounded quarterly (every 3 months) and the money is left for 6 years.
\n" ); document.write( "The final amount is $_____. Round answer to 2 decimal places
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Algebra.Com's Answer #717148 by Theo(13342)\"\" \"About 
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f = p * (1+r)^n\r
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\n" ); document.write( "\n" ); document.write( "f is the future value
\n" ); document.write( "p is the present value
\n" ); document.write( "r is the interest rate per time period.
\n" ); document.write( "n is the number of time periods.\r
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\n" ); document.write( "\n" ); document.write( "there are 4 quarters in a year.\r
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\n" ); document.write( "\n" ); document.write( "3% interest per year compounded quarterly gives you 3% / 4 = .75% interest rate per quarter.\r
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\n" ); document.write( "\n" ); document.write( ".75% interest rate per quarter is equal to .0075 interest rate per quarter.\r
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\n" ); document.write( "\n" ); document.write( ".0075 is the decimal equivalent of .75%.\r
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\n" ); document.write( "\n" ); document.write( "the decimal equivalent of the percent is what is used in the formula.\r
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\n" ); document.write( "\n" ); document.write( "6 years * 4 quarters per year = 24 quarters.\r
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\n" ); document.write( "\n" ); document.write( "you are given that p = 4700\r
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\n" ); document.write( "\n" ); document.write( "the equation of f = p * (1+r)^n becomes:\r
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\n" ); document.write( "\n" ); document.write( "f = 4700 * (1.0075)^24\r
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\n" ); document.write( "\n" ); document.write( "solve for f to get:\r
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\n" ); document.write( "\n" ); document.write( "f = 5623.143588\r
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\n" ); document.write( "\n" ); document.write( "if you are given the yearly interest rate and the number of years, then the formula can also be shown as:\r
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\n" ); document.write( "\n" ); document.write( "f = p * (1 + r/c) ^ (nc)\r
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\n" ); document.write( "\n" ); document.write( "f is the future value
\n" ); document.write( "p is the present value
\n" ); document.write( "r/c is the yearly interest rate divided by the number of compounding periods per year.
\n" ); document.write( "nc is the number of years multiplied by the compounding periods per year.\r
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\n" ); document.write( "\n" ); document.write( "your formula would have become f = 4700 * (1 + .03/4) ^ (6*4)\r
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\n" ); document.write( "\n" ); document.write( "this would have resulted in f = 5623.143588 which is the same answer as what was previously calculated above.\r
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