document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102389>Question 1102389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f(x)=log(2x+3), find:\r<BR>\n" );
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document.write( "a. range.<BR>\n" );
document.write( "b. domain.<BR>\n" );
document.write( "c. x-intercept.<BR>\n" );
document.write( "d. y-intercept.\r<BR>\n" );
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document.write( "Please show your work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717097 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717097\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = log(2x+3)<BR>\n" );
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document.write( "assume the log base is 10<BR>\n" );
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document.write( "range is all real numbers<BR>\n" );
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document.write( "domain is x > -3/2<BR>\n" );
document.write( "Note negative logarithms are not defined so x can not be < -3/2<BR>\n" );
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document.write( "since log base 10 of 1 is 0, the x intercept is (-1,0)<BR>\n" );
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document.write( "y intercept is when x = 0, this gives us (0, log base 10 of 3)<BR>\n" );
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document.write( "Here is solution for x intercept (-1, 0)<BR>\n" );
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document.write( "log(10) (2x+3) = log (2x+3) / log (10)<BR>\n" );
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document.write( "log (2x+3) / log (10) = 0<BR>\n" );
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document.write( "log (2x+3) = 0<BR>\n" );
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document.write( "remove log by taking exponent of both sides of =<BR>\n" );
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document.write( "2x + 3 = 1<BR>\n" );
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document.write( "2x = -2<BR>\n" );
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document.write( "x = -1<BR>\n" );
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