document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102389>Question 1102389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f(x)=log(2x+3), find:\r<BR>\n" );
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document.write( "a. range.<BR>\n" );
document.write( "b. domain.<BR>\n" );
document.write( "c. x-intercept.<BR>\n" );
document.write( "d. y-intercept.\r<BR>\n" );
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document.write( "Please show your work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717093 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f f(x)=log(2x+3), find: <BR>\n" );
document.write( "a. range.<BR>\n" );
document.write( "Since 2x+3 must be > 0, range All Real Numbers<BR>\n" );
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document.write( "b. domain.<BR>\n" );
document.write( "Since 2x+3 must be > 0, 2x+3 > 0 ; So, domain is All Real Numbers > -3/2<BR>\n" );
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document.write( "c. x-intercept.<BR>\n" );
document.write( "Let y = 0 ; Then 2x+3 = 10^0 ; So x = -2/2 = -1<BR>\n" );
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document.write( "d. y-intercept. <BR>\n" );
document.write( "Let x = 0 ; Then y = log(3)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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