document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98561>Question 98561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> With a tail wind*, a helicopter traveled 300 mi in 1 hr 40 min. The return trip against the same wind took 20 min longer. Find the wind speed* and also the air speed* of the helicopter.\r<BR>\n" );
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document.write( "*air speed- the speed of an aircraft in still air<BR>\n" );
document.write( "*wind speed- the speed of the wind<BR>\n" );
document.write( "*tail wind- a wind blowing in the same direction as the path of the aircraft. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #71709 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=71709\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 300/100=3 OR 3 MILES PER MINUTE=180 MPH<BR>\n" );
document.write( "300(120)=2.5 0R 2.5 MILES PER MINUTE OR 150 MPH.<BR>\n" );
document.write( "180-W=150+W<BR>\n" );
document.write( "-W-W=150-180<BR>\n" );
document.write( "-2W=-30<BR>\n" );
document.write( "W=-30/-2<BR>\n" );
document.write( "W=15 MPH FOR THE WIND.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "300/180=1 2/3 HOURS = 1 HOUR & 40 MINUTES.<BR>\n" );
document.write( "300/150=2 HOURS <BR>\n" );
document.write( "2 HRS-(1 HOUR & 40 MINUTES)=20 MINUTES LONGER FLIGHT.<BR>\n" );
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