document.write( "Question 1102397: Factorise 4x^2+12x+9
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Algebra.Com's Answer #717084 by KMST(5328) $\"\"$ $\"About$

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IN THIS CASE:
\n" ); document.write( "The terms of $\"4x%5E2%2B12x%2B9\"$ are
\n" ); document.write( " $\"4x%5E2=%28red%282x%29%29%5E2\"$ ,
\n" ); document.write( " $\"9=%28green%283%29%29%5E2\"$ , and
\n" ); document.write( " $\"12x=2%28red%282x%29%29%28green%283%29%29\"$ , so
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\n" ); document.write( "IN GENERAL:
\n" ); document.write( "When you have trouble factoring a polynomial of degree 2 with a coefficient different from $\"%22+%22+%2B-+1\"$ in front of $\"x%5E2\"$ ,
\n" ); document.write( "you can split the term in $\"x\"$ into two terms, and factor by parts,
\n" ); document.write( "like this:
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.
\n" ); document.write( "To find how to split the term in $\"x\"$ ,
\n" ); document.write( "look for factors of the product of the other two coefficients
\n" ); document.write( "(in this case, factors of $\"4%2A9=36\"$ ).
\n" ); document.write( "Look for a pair that adds up to the coefficient of $\"x\"$ ,
\n" ); document.write( "and when multiplied gives the product of the other two coefficients.
\n" ); document.write( "In this case $\"6%2A6=36\"$ and $\"6%2B6=12\"$ . \n" ); document.write( "

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