document.write( "Question 1102323: if $ 1000 is invested now, $ 1500 two years from now, $ 2000 four years from now on interest rate of 6% compound annually, how much money accumulates after 10 years? \n" ); document.write( "

Algebra.Com's Answer #717073 by Theo(13342) $\"\"$ $\"About$

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you are investing:\r
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\n" ); document.write( "\n" ); document.write( "1000 for 10 years.
\n" ); document.write( "1500 for 8 years.
\n" ); document.write( "2000 for 6 years.\r
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\n" ); document.write( "\n" ); document.write( "interest rate is 6% per year compounded annually.\r
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\n" ); document.write( "\n" ); document.write( "formula is f = p * (1+r)^n\r
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\n" ); document.write( "\n" ); document.write( "f is the future value.
\n" ); document.write( "p is the present value
\n" ); document.write( "r is the interest rate per time period (years in this case).
\n" ); document.write( "n is the number of time periods (years in this case).\r
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\n" ); document.write( "\n" ); document.write( "first formula is f1 = 1000 * 1.06^10
\n" ); document.write( "second formula is f2 = 1500 * 1.06^8
\n" ); document.write( "third formula is f3 = 2000 * 1.06^6\r
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\n" ); document.write( "\n" ); document.write( "solution is f1 + f2 + f3 which is equal to 1790.847697 + 2390.772112 + 2837.038225 = 7018.658033.\r
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