document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102259>Question 1102259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sin(2x) = -sqrt(2)/2\r<BR>\n" );
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document.write( "have to find what points on the unit circle would equal that </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #717006 by </B><A HREF=/tutors/aboutme.mpl?userid=Lightning_Fast><B>Lightning_Fast(78)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Lightning_Fast><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Lightning_Fast><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=717006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well the 2x there is a little crazy, so replace 2x with z. In other words, z = 2x.\r<BR>\n" );
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document.write( " Now the equation is:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sin%28z%29+=+-sqrt%282%29%2F2 ALIGN=MIDDLE  ALT=\"sin%28z%29+=+-sqrt%282%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now from the unit circle, we know that z must be equal to 125 and 315 degrees. Now you know what z is in degrees, you can use the previous equation.\r<BR>\n" );
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document.write( "z = 2x\r<BR>\n" );
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document.write( "Now you obtain the following.<BR>\n" );
document.write( "125 = 2x\r<BR>\n" );
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document.write( "315 = 2x\r<BR>\n" );
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document.write( "Now use algebra and solve for x. But remember the x value is NOT the point on the unit circle that will equal -sqrt(2)/2. It is just a solution to the equation.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=Lightning_Fast&illustration_name=photograph13\">\r<BR>\n" );
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document.write( "If you want to find the points on the unit circle that satisfy this equation, you just have to look at the unit circle.\r<BR>\n" );
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document.write( "The values appear to be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-sqrt%282%29%2F2 ALIGN=MIDDLE  ALT=\"-sqrt%282%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > , <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-sqrt%282%29%2F2%29 ALIGN=MIDDLE  ALT=\"-sqrt%282%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >) and (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=++sqrt%282%29%2F2+ ALIGN=MIDDLE  ALT=\"++sqrt%282%29%2F2+\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-sqrt%282%29%2F2 ALIGN=MIDDLE  ALT=\"-sqrt%282%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >)<BR>\n" );
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