document.write( "Question 98548: A clown weighs 60lb more than a trapeze artist.the trapeze artist weighs two thirds as much as the clown.How much does each weigh.
\n" ); document.write( "choices for the weigh of the trapeze artist.110,120,125
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Algebra.Com's Answer #71699 by WannabeCAgirl83(35)\"\" \"About 
You can put this solution on YOUR website!
Here you go...\r
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\n" ); document.write( "\n" ); document.write( "clown: \"c+=+t%2B60\"
\n" ); document.write( "trapeze artist: \"t=%282%2F3%29c\"\r
\n" ); document.write( "\n" ); document.write( "You cannot work with two variables. One of them has to \"disappear\" for you to be able to solve this.\r
\n" ); document.write( "\n" ); document.write( "As t is the same as \"%282%2F3%29c\", you can substitue \"%282%2F3%29c\" for t as follows:\r
\n" ); document.write( "\n" ); document.write( "\"c+=+t%2B60\" substitute for t...
\n" ); document.write( "\"c+=+%282%2F3%29c%2B60\" multiply by LCD 3...
\n" ); document.write( "\"3c+=+2c%2B180\" subtract 2c...
\n" ); document.write( "\"c+=+180\" ---> The clown ways 180 lbs.\r
\n" ); document.write( "\n" ); document.write( "As the problem stated that the clown weighs 60 lbs more than the trapeze artist, you subtract 60 from 180 to get the weight for the trapeze artist: 120 lbs.\r
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