document.write( "Question 98545This question is from textbook Calculus with Applications Brief Version
\n" ); document.write( ": I'm having trouble solving for 'x' in this equation $\"log4%28x-2%29%2B+log4%28x%2B6%29=2\"$ . I have tried re-arranging it to make an exponential equation, but I end up confusing myself even more. \r
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Algebra.Com's Answer #71695 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
log4(x-2)+ log4(x+6)=2
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\n" ); document.write( "Note: Keep the \"base 4\" in mind
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\n" ); document.write( "log(x-2)(x+6) = 2
\n" ); document.write( "(x-2)(x+6) = 4^2
\n" ); document.write( "x^2+4x-12 = 16
\n" ); document.write( "x^2+4x-28=0
\n" ); document.write( "x = [-4 +- sqrt(16-4*-28]/2\r
\n" ); document.write( "\n" ); document.write( "x = [-4 +- sqrt(128)]/2
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\n" ); document.write( "\n" ); document.write( "x = [-4 + 8sqrt(2)]/2 = -2+4sqrt2
\n" ); document.write( "OR
\n" ); document.write( "x = [-4 - 8sqrt(2)]/2 = -2-4sqrt2\r
\n" ); document.write( "\n" ); document.write( "====================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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