document.write( "Question 1102186: solve the equation
\n" ); document.write( "2sin^2(x -30) = cos 60 for (-180 > x > 180)
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Algebra.Com's Answer #716903 by stanbon(75887)\"\" \"About 
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solve the equation
\n" ); document.write( "2sin^2(x -30) = cos 60 for (-180 > x > 180)
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\n" ); document.write( "2sin^2(x-30) = 1/2
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\n" ); document.write( "sin^2(x-30) = 1/4
\n" ); document.write( "sin(x-30) = 1/2 or sin(x-30) = -1/2
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\n" ); document.write( "x-30 = 30
\n" ); document.write( "x = 60
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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