document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102245>Question 1102245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangular rug has an area of 96 square feet and a perimeter of 4o feet. The length is grater than the width. Suppose the width is x feet. Use the fact that the perimeter is 40 feet to find an expression for the light as a function of x. Find the length and width of the rug.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716901 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width is x<BR>\n" );
document.write( "length is 20-x, so half perimeter is 20 (L+W).<BR>\n" );
document.write( "Area is x(20-x) and that equals 96<BR>\n" );
document.write( "therefore 20x-x^2=96<BR>\n" );
document.write( "x^2-20x+96=0<BR>\n" );
document.write( "(x-12)(x-8)=0<BR>\n" );
document.write( "x=12 feet or 8 feet.<BR>\n" );
document.write( "Use 8 feet for width since given that width is smaller.<BR>\n" );
document.write( "It is 8 ft x 12 ft.<BR>\n" );
document.write( "That is an area of 96 ft^2. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );