document.write( "Question 98540: Find all real or imaginary solutions to each equation. Use the method of your choice.
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Algebra.Com's Answer #71690 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's use the quadratic formula to solve for v:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"av%5E2%2Bbv%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"v+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"3%2Av%5E2%2B4%2Av-1=0\" ( notice \"a=3\", \"b=4\", and \"c=-1\")\r
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\n" ); document.write( "\n" ); document.write( "\"v+=+%28-4+%2B-+sqrt%28+%284%29%5E2-4%2A3%2A-1+%29%29%2F%282%2A3%29\" Plug in a=3, b=4, and c=-1\r
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\n" ); document.write( "\n" ); document.write( "\"v+=+%28-4+%2B-+sqrt%28+16-4%2A3%2A-1+%29%29%2F%282%2A3%29\" Square 4 to get 16 \r
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\n" ); document.write( "\n" ); document.write( "\"v+=+%28-4+%2B-+sqrt%28+16%2B12+%29%29%2F%282%2A3%29\" Multiply \"-4%2A-1%2A3\" to get \"12\"\r
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\n" ); document.write( "\n" ); document.write( "\"v+=+%28-4+%2B-+sqrt%28+28+%29%29%2F%282%2A3%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"v+=+%28-4+%2B-+2%2Asqrt%287%29%29%2F%282%2A3%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"v+=+%28-4+%2B-+2%2Asqrt%287%29%29%2F6\" Multiply 2 and 3 to get 6\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"v+=+%28-4+%2B+2%2Asqrt%287%29%29%2F6\" or \"v+=+%28-4+-+2%2Asqrt%287%29%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"v=-4%2F6%2B2%2Asqrt%287%29%2F6\" or \"v=-4%2F6-2%2Asqrt%287%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"v=-2+%2F+3%2Bsqrt%287%29%2F3\" or \"v=-2+%2F+3-sqrt%287%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"v=0.21525043702153\" or \"v=-1.54858377035486\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"v=0.21525043702153\" or \"v=-1.54858377035486\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"3%2Ax%5E2%2B4%2Ax-1\" (just replace v with x), we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=0.21525043702153\" and \"x=-1.54858377035486\".So this verifies our answer
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