document.write( "Question 1102223: What is the sum of all natural numbers between 1 and 200 which are multiples of 5? \n" ); document.write( "
Algebra.Com's Answer #716896 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "This will be pretty much the same answer as provided by the other tutor, but using informal logical analysis instead of formal mathematical formulas.

\n" ); document.write( "Assuming that \"between 1 and 200\" includes 200, the sum is 5+10+...+195+200.

\n" ); document.write( "The number of terms in the sum is 200/5 = 40.

\n" ); document.write( "Since the numbers are equally spaced, the 40 numbers can be paired into 20 pairs, each with a sum of 205: 5+200 = 205; 10+195 = 205; 15+190 = 205; etc.

\n" ); document.write( "So the sum of all the numbers is the sum of 20 pairs, with each pair having a sum of 205: 205*20 = 4100.

\n" ); document.write( "And here is an alternative way to think about getting the final sum, once we have found that there are 40 terms in the sum.

\n" ); document.write( "Again since the numbers are equally spaced, the average of all the terms is the average of the first and last terms: (5+200)/2 = 102.5

\n" ); document.write( "Then the sum of all the numbers is that average, multiplied by the number of terms: 40(102.5) = 4100.

\n" ); document.write( "To summarize these two different ways of finding the sum, we have either

\n" ); document.write( "(a) (number of pairs)*(sum of first and last) = \"%28n%2F2%29%28a1%2Ban%29\"
\n" ); document.write( "or
\n" ); document.write( "(b) (number of numbers)*(average of first and last) = \"n%28%28a1%2Ban%29%2F2%29\"

\n" ); document.write( "Those two formulas, representing different ways of thinking of getting the answer, are clearly mathematically equivalent.
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