document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1102209>Question 1102209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4.	A committee of 5 people is to be formed randomly from a group of 10 women and 6 men. Find the probability that the committee has \r<BR>\n" );
document.write( "\n" );
document.write( "a)	3 women and 2 men. \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "b)	5 women. \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c) At least 4 women.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716873 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The denominator is 16C5=4368<BR>\n" );
document.write( "a) numerator is 10C3*6C2=120*15=1800, so that probability is 0.4121<BR>\n" );
document.write( "b) 10C5*6C0*1=252, probability is 0.0577<BR>\n" );
document.write( "c) 10C4*6C1=210*6=1260, probability is 0.2885 PLUS probability of 5 women, which is 0.0577 for overall probability of 0.3462, adding, and using the numerators above get an exact answer which rounds to the same number. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );