document.write( "Question 1102209: 4. A committee of 5 people is to be formed randomly from a group of 10 women and 6 men. Find the probability that the committee has \r
\n" ); document.write( "\n" ); document.write( "a) 3 women and 2 men. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "b) 5 women. \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "c) At least 4 women.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #716872 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
4. A committee of 5 people is to be formed randomly from a group of 10 women and 6 men. Find the probability that the committee has \r
\n" ); document.write( "\n" ); document.write( "a) 3 women and 2 men.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "
b) 5 women.
c) At least 4 women.
\r\n" );
document.write( "That's the probability of 5 women plus the probability of\r\n" );
document.write( "4 women and 1 man. Part (b) is the probability of 5 women,\r\n" );
document.write( "so we only need to add the probability of 4 women and 1 man\r\n" );
document.write( "to the 3/52 we got in part (b).  \r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "So we add the two:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );