document.write( "Question 1102180: Two​ mechanics, Bonita Rich and Pamela​ Pearson, take 5 hours to rebuild an engine when they work together. If each worked​ alone, Bonita, the more experienced​ mechanic, could complete the job 3 hours faster than Pamela. How long would it take each of them to rebuild the engine working​ alone? \n" ); document.write( "
Algebra.Com's Answer #716837 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
1/x+1/(x+3)=1/5
\n" ); document.write( "(5*x*(x+3))/x+(5*x*(x+3))/(x+3)=(5*x*(x+3))/5
\n" ); document.write( "(5*(x+3))+5*x=x*(x+3)
\n" ); document.write( "5*x+15+5*x=x^2+3*x
\n" ); document.write( "10*x+15=x^2+3*x
\n" ); document.write( "x^2-7*x-15=0
\n" ); document.write( "Can it be factored?
\n" ); document.write( "What factors of -15 add up to -7?
\n" ); document.write( "Nevertheless, we will complete the square
\n" ); document.write( "x^2-7*x=15
\n" ); document.write( "Add it.
\n" ); document.write( "x^2-7*x+(-7/2)=15+(-7/2)
\n" ); document.write( "Square it.
\n" ); document.write( "x^2-7*x+(49/4)=15+(49/4)
\n" ); document.write( "x^2-7*x+(12.25)=15+(12.25)
\n" ); document.write( "x^2-7*x+(12.25)=27.25
\n" ); document.write( "(x-3.5)^2=27.25
\n" ); document.write( "(x-3.5)^2=27.25
\n" ); document.write( "We will continue.
\n" ); document.write( "x+-3.5=(+-)5.22015325
\n" ); document.write( "x=3.5(+-)5.22015325
\n" ); document.write( "Positive useful answer:
\n" ); document.write( "x=3.5+5.22015325
\n" ); document.write( "One worker is x=8.72015325
\n" ); document.write( "x+3=3+8.72015325
\n" ); document.write( "x+3=11.7201533
\n" ); document.write( "Other worker =11.7201533
\n" ); document.write( "check
\n" ); document.write( "1/x+1/(x+3)=1/5
\n" ); document.write( "1/8.72015325+1/(8.72015325+3)=1/5
\n" ); document.write( "1/8.72015325+1/11.7201533=1/5
\n" ); document.write( "11.7201533/102.201533+8.72015325/102.201533=1/5
\n" ); document.write( "20.4403065/102.201533=1/5
\n" ); document.write( "0.2=0.2
\n" ); document.write( "ok\r
\n" ); document.write( "\n" ); document.write( "Useless answer:
\n" ); document.write( "x=3.5-5.22015325
\n" ); document.write( "Useless answer is x=-1.72015325
\n" ); document.write( " x =-1.72015325
\n" ); document.write( " This answer is useless because it is Negative
\n" ); document.write( "For real life cases involving time, distance and other measurements, we reject the negative results
\n" ); document.write( "codewtp\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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