document.write( "Question 1102088: student receives test scores of 52, 83, and 91. The student final exam is 88 and homework score is 76. Each test is worth 20% the final exam is worth 25%, and the homework grade is worth 15%. What is the students mean score in the class?\r
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Algebra.Com's Answer #716832 by Theo(13342)\"\" \"About 
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the procedure is shown in the following excel spreadsheet printout.\r
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\n" ); document.write( "\n" ); document.write( "in this particular case, the sum of frequency data is 1 because we are dealing with frequency data being a percent of the total.\r
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\n" ); document.write( "\n" ); document.write( "the procedure still requires you to divide by the sum of the frequency data because you will not always be dealing with frequency as a percent of the total.\r
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\n" ); document.write( "\n" ); document.write( "in that case, the sum of the frequency data will be something other than 1.\r
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\n" ); document.write( "\n" ); document.write( "the following excel printout shows you the same data with frequency as a percent rather than as a decimal equivalent of percent.\r
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\n" ); document.write( "\n" ); document.write( "the sum of frequency data is now 100 rather than 1.\r
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\n" ); document.write( "\n" ); document.write( "the following excel printout shows you the same data with frequency as 5 times the frequency as a percent rather than the frequency as a percent.\r
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\n" ); document.write( "\n" ); document.write( "the sum of frequency data is now 500 rather than 100\r
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\n" ); document.write( "\n" ); document.write( "in all cases, the weighted average and the weighted variance and the weighted standard deviation are all the same.\r
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