document.write( "Question 1102143: An open box is formed from a rectangular piece of cardboard that is 3 in. longer than it is wide, by removing squares of side 2 in. from each corner and folding up the sides. If the volume of the carton is then 216 in^3, what were the dimensions of the original piece of cardboard? \n" ); document.write( "
Algebra.Com's Answer #716798 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
continuing Stan's work before he erred.
\n" ); document.write( "
\n" ); document.write( "Volume = length * width * height
\n" ); document.write( "216 = (w-1)*(w-4)*w
\n" ); document.write( "height =2
\n" ); document.write( "216 = (w-1)*(w-4)*2
\n" ); document.write( "108=(w-1)*(w-4)
\n" ); document.write( "108=w^2-5w+4
\n" ); document.write( "0=w^2-5w-104
\n" ); document.write( "factor
\n" ); document.write( "(w+8)*(w-13)=0
\n" ); document.write( "Taking only the positive solution
\n" ); document.write( "original w=13 inches
\n" ); document.write( "cardboard that is 3 in. longer than it is wide
\n" ); document.write( "original length=w+3=16 inches\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );