document.write( "Question 1102143: An open box is formed from a rectangular piece of cardboard that is 3 in. longer than it is wide, by removing squares of side 2 in. from each corner and folding up the sides. If the volume of the carton is then 216 in^3, what were the dimensions of the original piece of cardboard? \n" ); document.write( "
Algebra.Com's Answer #716791 by stanbon(75887)\"\" \"About 
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An open box is formed from a rectangular piece of cardboard that is 3 in. longer than it is wide, by removing squares of side 2 in. from each corner and folding up the sides. If the volume of the carton is then 216 in^3, what were the dimensions of the original piece of cardboard?
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\n" ); document.write( "Original dimensions of the rectangular piece::
\n" ); document.write( "width = w inches
\n" ); document.write( "length = w+3 inches
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\n" ); document.write( "After cutting out the 2 by 2 squares the remaining width and length dimensions are:
\n" ); document.write( "new width :: w-4 inches
\n" ); document.write( "new length:: w+3-4 = w-1 inches
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\n" ); document.write( "Volume = length * width * height
\n" ); document.write( "216 = (w-1)*(w-4)*w
\n" ); document.write( "216 = (w^2-5w+4)*w
\n" ); document.write( "w^3 - 5w^2 + 4w - 216 = 0
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\n" ); document.write( "w = 7.93 (original width)
\n" ); document.write( "w+3 = 10.93 (original length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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