document.write( "Question 98517: i need help with this... Solve simultaneously:\r
\n" ); document.write( "\n" ); document.write( "\"2log+y+=+log+2+%2B+log+x\" , \"2%5Ey=4x\"\r
\n" ); document.write( "\n" ); document.write( "what ive got so far is : \"y%5E2=log+2x\" , and \"y=log+%28base+2%29+4x\"
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Algebra.Com's Answer #71677 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2log y = log 2 + log x , 2^y=4x\r
\n" ); document.write( "\n" ); document.write( "-----------------------
\n" ); document.write( "log(y^2/x) = log(2)
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\n" ); document.write( "1st: y^2 = 2x
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\n" ); document.write( "2nd: 2^y = 4x
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\n" ); document.write( "Multiply 1st by 2 to get:
\n" ); document.write( "2y^2=4x
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\n" ); document.write( "Therefore 2y^2 = 2^y
\n" ); document.write( "y^2 = 2^(y-1)
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\n" ); document.write( "Solution: y = 1
\n" ); document.write( "Substitute into 2logy=log2+logx
\n" ); document.write( "0 = log2 +logx
\n" ); document.write( "0=log(2x)
\n" ); document.write( "2x = 1
\n" ); document.write( "x = 1/2
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\n" ); document.write( "Check x=1/2 and y=1 in 2^y=4x
\n" ); document.write( "2^1 = 4(1/2)
\n" ); document.write( "2 = 2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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