document.write( "Question 98517: i need help with this... Solve simultaneously:\r
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document.write( "what ive got so far is : , and
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Algebra.Com's Answer #71677 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2log y = log 2 + log x , 2^y=4x\r \n" ); document.write( "\n" ); document.write( "----------------------- \n" ); document.write( "log(y^2/x) = log(2) \n" ); document.write( "--------------------------------- \n" ); document.write( "1st: y^2 = 2x \n" ); document.write( "------------------ \n" ); document.write( "2nd: 2^y = 4x \n" ); document.write( "-------------- \n" ); document.write( "Multiply 1st by 2 to get: \n" ); document.write( "2y^2=4x \n" ); document.write( "------------ \n" ); document.write( "Therefore 2y^2 = 2^y \n" ); document.write( "y^2 = 2^(y-1) \n" ); document.write( "-------------- \n" ); document.write( "Solution: y = 1 \n" ); document.write( "Substitute into 2logy=log2+logx \n" ); document.write( "0 = log2 +logx \n" ); document.write( "0=log(2x) \n" ); document.write( "2x = 1 \n" ); document.write( "x = 1/2 \n" ); document.write( "---------------- \n" ); document.write( "Check x=1/2 and y=1 in 2^y=4x \n" ); document.write( "2^1 = 4(1/2) \n" ); document.write( "2 = 2 \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |