document.write( "Question 1102132: The area of a triangular flag is 132 square centimeters. Its altitude is 2 centimeters longer than twice its base. Find the lengths of the altitude and the base. THANK YOU!! \n" ); document.write( "

Algebra.Com's Answer #716763 by ikleyn(52832) $\"\"$ $\"About$

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document.write( "You are given\r\n" );
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document.write( "0.5*A*B = 132    (1)   (area = 0.5 * (Altitude A) multiplied by (Base B) )\r\n" );
document.write( "A = 2B +2.       (2)\r\n" );
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document.write( "===============>  by substitution (2) into (1)  ============>\r\n" );
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document.write( "(2B + 2)*B = 264,\r\n" );
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document.write( "2B^2 + 2B - 264 = 0  ====>\r\n" );
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document.write( "B^2 + B - 132 = 0\r\n" );
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document.write( "(B+12)*(B-11) = 0.\r\n" );
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document.write( "Only positive root makes sense:  B = 11 cm.\r\n" );
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document.write( "Altitude = 2B + 2 = 2*11 + 2 = 24 cm.\r\n" );
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