document.write( "Question 98505: A circular sheet of paper of radius 6 cm is cut into three equal sectors, and each sector is formed into a cone with no overlap. What is the height in centimeters of each cone? \n" ); document.write( "
Algebra.Com's Answer #71676 by Earlsdon(6294)\"\" \"About 
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We could find the height of the resulting cone if we knew their slant-height and radius.
\n" ); document.write( "Starting with the circular sheet of paper whose radius (R) is 6 cm. If you divide this into three equal sectors to form the cones, then each cone will have a slant-height equal to the radius of the original circle, right?
\n" ); document.write( "Now the circumference of the base of each cone will be equal to one third of the circumference of the original circle.
\n" ); document.write( "The circumference (C) of the original circle is:
\n" ); document.write( "\"C+=+2%28pi%29R\" and, of course, you know that R is 6 cm, so...
\n" ); document.write( "\"C+=+12%28pi%29\" Divide both sides by 3 to find one third of this.
\n" ); document.write( "\"C%2F3+=+4%28pi%29\" and this is the circumference (c) of the cone base.
\n" ); document.write( "From this we can find the radius (r) of the cone base because \"c+=+2%28pi%29r\" but this is equal to \"4%28pi%29\". So we can write:
\n" ); document.write( "\"2%28pi%29r+=+4%28pi%29\" Simplifying, we get:
\n" ); document.write( "\"2r+=+4\" and so...
\n" ); document.write( "\"r+=+2\" this is the radius of the cone base.
\n" ); document.write( "Now we can use the Pythagorean theorem to find the cone height using the slant-height of the cone (6 cm) as the hypotenuse of a right triangle and the radius of the cone base (2 cm) as the base of a right triangle.
\n" ); document.write( "\"6%5E2+=+2%5E2+%2B+h%5E2\" where h is the height of the cone.
\n" ); document.write( "\"36+=+4+%2B+h%5E2\" Subtract 4 from both sides.
\n" ); document.write( "\"h%5E2+=+32\" Take the square root of both sides.
\n" ); document.write( "\"h+=+5.657\"cm. This is the height of the cone to the nearest thousandth.
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