document.write( "Question 1102125: Joe maintains a special account just for entertainment. One week, he spends 20% of this account of entertainment. The next week, he spends 25% of what remains on entertainment. After the two weeks, Joe ends up with y dollars in this account. How much did Joe originally have in his special entertainment account? \n" ); document.write( "
Algebra.Com's Answer #716758 by stanbon(75887)\"\" \"About 
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Joe maintains a special account just for entertainment. One week, he spends 20% of this account of entertainment. The next week, he spends 25% of what remains on entertainment. After the two weeks, Joe ends up with y dollars in this account. How much did Joe originally have in his special entertainment account?
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\n" ); document.write( "start:: x
\n" ); document.write( "after one week:: 0.8x
\n" ); document.write( "After next week: 0.75(0.8x) == 0.6x
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\n" ); document.write( "Equation:
\n" ); document.write( "0.6x = y
\n" ); document.write( "Ans:: x = 10y/6 = (5/3)y
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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