document.write( "Question 1102100: A 20% solution of fertilizer is to be mixed with a 50% solution of fertilizer in order to get 60 gallons of a 40% solution. How many gallons of the 20% and 50% solution should be mixed? \n" ); document.write( "
Algebra.Com's Answer #716739 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! Let A denote the 50% solution and B denote the 20% solution which we have. \n" ); document.write( "Let C denote the 40% solution which we want. \n" ); document.write( "Using the method of alligation. \n" ); document.write( " \r\n" ); document.write( "50 20 20/30*60=40 gal of 50% solution\r\n" ); document.write( " 40 40+20= 60 gal of 40% solution\r\n" ); document.write( "20 10 10/30*60=20 gal of 20% solution\r\n" ); document.write( " 30\r\n" ); document.write( " \n" ); document.write( "10= 50 - 40 \n" ); document.write( "20= 40 - 20 \n" ); document.write( "20+10=30 parts total \n" ); document.write( "There are 60 gal total \n" ); document.write( " \r\n" ); document.write( "50 20 20/30*60=40 gal of 50% solution\r\n" ); document.write( " \n" ); document.write( "20/30*60=40 \n" ); document.write( "40 gal of 50% solution. \n" ); document.write( "60-40=20 gal \n" ); document.write( " \r\n" ); document.write( "20 10 10/30*60=20 gal of 20% solution\r\n" ); document.write( " \n" ); document.write( "20 gal of 20% solution.\r \n" ); document.write( "\n" ); document.write( "check \n" ); document.write( "0.2 * 20 + 0.5 * 40 = 0.4*60 \n" ); document.write( "4.0 + 20.0 = 24.0 \n" ); document.write( "24.0 = 24.0 \n" ); document.write( "ok\r \n" ); document.write( "\n" ); document.write( "Now using algebra \n" ); document.write( "We need a total of 60 gal at 40% \n" ); document.write( "We want to know how many gal at 20% to mix with 50% \n" ); document.write( "a+b=60 \n" ); document.write( "0.2*a+0.5*b=0.4*60 \n" ); document.write( "a=60-b \n" ); document.write( "0.2*(60-b)+0.5*b=24 \n" ); document.write( "12-0.2b+0.5*b=24 \n" ); document.write( "0.3*b=12 \n" ); document.write( "b=40 \n" ); document.write( "a=60-b \n" ); document.write( "a=20 gal at 20% \n" ); document.write( "b=40 gal at 50% \n" ); document.write( "check \n" ); document.write( "0.2*20+0.5*40=0.4*60 \n" ); document.write( "4+20=24 \n" ); document.write( "24=24 \n" ); document.write( "ok \n" ); document.write( "codemx1 \n" ); document.write( " \n" ); document.write( " |