document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101988>Question 1101988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me? Thank you. <BR>\n" );
document.write( "I need to make it clear about the hyperbola. X^2-y^2=1 is transformed T(x,y)=(ax+h, by+k). How do I write the equation after transformation? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716716 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "start with T(x,y) = x^2 - y^2\r<BR>\n" );
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document.write( "when T(x,y) = 1, then the equation becomes x^2 - y^2 = 1\r<BR>\n" );
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document.write( "when you want T(ax+h,by+k), then you simply replace x with ax+h and y with by+k and you get:\r<BR>\n" );
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document.write( "T(ax+h,by+k) = (ax+h)^2 - (by+k)^2\r<BR>\n" );
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document.write( "when T(ax+h,by+k) is equal to 1, then the equation becomes (ax+h)^2 - (by+k)^2 = 1\r<BR>\n" );
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document.write( "that's what i think your solution will be.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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