document.write( "Question 1102037: Show, by the Principle of Mathematical Induction:
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document.write( "8 + 16 + 24+…+8n = 4n(n+1) for n≥1 \n" );
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Algebra.Com's Answer #716664 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Show, by the Principle of Mathematical Induction: \n" ); document.write( "8 + 16 + 24+…+8n = 4n(n+1) for n≥1 \n" ); document.write( "----- \n" ); document.write( "Show it is true for n = 1 \n" ); document.write( "8 = 4(2) \n" ); document.write( "------------------- \n" ); document.write( "Assume it is true for n = k \n" ); document.write( "8 + 2*8 + 3*8 + ... + 8k = 4k(k+1) \n" ); document.write( "------------------------ \n" ); document.write( "Show that it must be true for n = k+1 \n" ); document.write( "8 + 2*8 + 3*8 + ... + 8k + (k+1)8 = 4(k+1)(k+2) \n" ); document.write( "------ \n" ); document.write( "Note:: The 1st 8 terms = 4k(k+1) so you get:: \n" ); document.write( "4k(k+1) + (k+1)(8) = (k+1)[4k+8] = (k+1)*4(k+2) = 4(k+1)(k+2) \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " |