document.write( "Question 1102026: The population of Adams Ville grew from 10,000 to 18,000 in five years. Assuming uninhibited exponential growth, what is the expected population in an additional two years \n" ); document.write( "
Algebra.Com's Answer #716652 by stanbon(75887)\"\" \"About 
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The population of Adamsville grew from 10,000 to 18,000 in five years. Assuming uninhibited exponential growth, what is the expected population in an additional two years.
\n" ); document.write( "Model:: pop = a*b^t
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\n" ); document.write( "At time 0 the population is 10000
\n" ); document.write( "i,e, 10,000 = a*b^0
\n" ); document.write( "So, a = 10,000
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\n" ); document.write( "At time = 5 years the pop is 18000
\n" ); document.write( "pop = 10000*b^5
\n" ); document.write( "18000 = 10000*b^5
\n" ); document.write( "1.8 = b^5
\n" ); document.write( "b = 8^(1/5) = 1.1247
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\n" ); document.write( "Equation::
\n" ); document.write( "pop = 10,000*1.1247^t
\n" ); document.write( "----
\n" ); document.write( "In an additional 2 yrs, t = 7
\n" ); document.write( "Then pop = 10000*1.1247 = 22765 when rounded up
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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