document.write( "Question 1102026: The population of Adams Ville grew from 10,000 to 18,000 in five years. Assuming uninhibited exponential growth, what is the expected population in an additional two years \n" ); document.write( "
Algebra.Com's Answer #716651 by josgarithmetic(39630)\"\" \"About 
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\"y=a%2Ab%5Ex\"\r
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\n" ); document.write( "\n" ); document.write( "\"18000=10000%2Ab%5E5\"
\n" ); document.write( "\"18%2F10=b%5E5\"
\n" ); document.write( "\"9%2F5=b%5E5\"\r
\n" ); document.write( "\n" ); document.write( "\"b%5E5=9%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28b%5E5%29%29=log%28%289%29%29-log%28%285%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"5%2Alog%28%28b%29%29=log%28%289%29%29-log%28%285%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28b%29%29=%28log%28%289%29%29-log%28%285%29%29%29%2F5\"\r
\n" ); document.write( "\n" ); document.write( "In base ten logs,\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28b%29%29=%280.95424-0.69897%29%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28b%29%29=0.051054\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=10%5E%280.051054%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28b=1.125%29\"\r
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\n" ); document.write( "\n" ); document.write( "MODEL: \"highlight%28y=10000%2A%281.125%29%5Ex%29\"\r
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\n" ); document.write( "\n" ); document.write( "Additional 2 years past the 5 means you use x=7 and evaluate \"10000%281.125%29%5E7\".
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