document.write( "Question 1101908: Members of the healthy running club ran from their club house to a first rest stop at a speed of 9 km/h, and from there to the second rest stop at a speed of 5 km/h. They returned along the same course, running at 10 km/h from the second rest stop to the first,and at 6 km/h the rest of the way to the club house. If it took a total of 2.5 h to run both ways between the club house and the first rest stop, and 3 hours to run both ways between the first and second rest stops, how far, in km, did they run altogether? \n" ); document.write( "
Algebra.Com's Answer #716616 by richwmiller(17219) You can put this solution on YOUR website! Members of the healthy running club ran from their club house to a first rest stop at a speed of 9 km/h, and from there to the second rest stop at a speed of 5 km/h. They returned along the same course, running at 10 km/h from the second rest stop to the first,and at 6 km/h the rest of the way to the club house. If it took a total of 2.5 h to run both ways between the club house and the first rest stop, and 3 hours to run both ways between the first and second rest stops, how far, in km, did they run altogether? \n" ); document.write( "ch->1rs->2rs \n" ); document.write( "9a+5x \n" ); document.write( "2rs->1rs->ch \n" ); document.write( "10y+6b\r \n" ); document.write( "\n" ); document.write( "x+y=3 \n" ); document.write( "a+b=2.5 \n" ); document.write( "9a+5x=10y+6b 1st to +2nd to =2nd fro+1st fro \n" ); document.write( "9a=6b \r \n" ); document.write( "\n" ); document.write( "a=6b/9 \n" ); document.write( "a=2b/3 \n" ); document.write( "a+b=2.5 \n" ); document.write( "2b/3+b=2.5 \n" ); document.write( "2b+3b=7.5 \n" ); document.write( "5b=7.5 \n" ); document.write( "b=7.5/5 \n" ); document.write( "b=1.5 \n" ); document.write( "a+b=2.5 \n" ); document.write( "a=1 \n" ); document.write( "5x=10y \n" ); document.write( "x=2y \n" ); document.write( "x+y=3 \n" ); document.write( "2y+y=3 \n" ); document.write( "3y=3 \n" ); document.write( "y=1 \n" ); document.write( "x=2 \n" ); document.write( "a=1 \n" ); document.write( "b=1.5 \n" ); document.write( "10y+6b \n" ); document.write( "10*1+6*1.5 \n" ); document.write( "10+9=19 km \n" ); document.write( "check \n" ); document.write( "9a+5x \n" ); document.write( "9+10=19 \n" ); document.write( "ok\r \n" ); document.write( "\n" ); document.write( "We really only needed to solve for (a and x) or (b and y). \n" ); document.write( " |