document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1101892>Question 1101892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An industrialist has 450 litres of a chemical which is 70% pure.  he mixes it with a chemical of the same type but 90% pure so as to obtain a mixture which is 75% . pure. find the amount of the 90%  pure chemical used. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #716530 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=716530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An industrialist has 450 litres of a chemical which is 70% pure.  He mixes it with a chemical of the same type but 90% pure so as to obtain a mixture which is 75% . pure. Find the amount of the 90%  pure chemical used. <BR>\n" );
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document.write( "The industrialist has no pure chemical as far as we know.<BR>\n" );
document.write( "He has on hand a mixture which is 70% and a mix that is 90% and wants to blend them to get a mix that is 75%<BR>\n" );
document.write( "Pure means 100%<BR>\n" );
document.write( "The 70% mix is a blend of 30%*450 = 125 L something else and 70 %*450 =315 L pure <BR>\n" );
document.write( "Otherwise, the math presented is correct.\r<BR>\n" );
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document.write( "We have on hand 450 L of 70% solution.<BR>\n" );
document.write( "Using the method of alligation.\r<BR>\n" );
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document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
document.write( "90         5 5/15*450=150 L of 90% solution\r\n" );
document.write( "      75            600 L of 75% solution\r\n" );
document.write( "70         15        450 L of 70% solution\r\n" );
document.write( "           20\r\n" );
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document.write( "check<BR>\n" );
document.write( "0.9 * 150 + 0.7 * 450 = 0.75*(450+150)<BR>\n" );
document.write( "135.0 + 315.0 = 0.75*(600)<BR>\n" );
document.write( "450.0 = 450.0<BR>\n" );
document.write( "ok<BR>\n" );
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