document.write( "Question 1101866: A man can do a job in 10 hours and his younger son can do it in 12 hours. After the father and his younger son have been working for 1 hour, the older son joins them, and the three completed the job in 3 more hours. How long will it take the older son to do the job?
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Algebra.Com's Answer #716489 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The other tutor's answer is right. \n" ); document.write( "Here is my solution, by a slightly different method that looks easier than what they did. \n" ); document.write( "As the other tutor showed in her calculations, the man and the younger son can do 11/60 of the job in 1 hour. \n" ); document.write( "When the older son joins them, the job is finished in another 3 hours. \n" ); document.write( "That means the man and his younger son work for 4 hours, and the older son works for 3. \n" ); document.write( "Since the man and the younger son do 11/60 of the job in 1 hour, they do 44/60 of the job in 4 hours. \n" ); document.write( "That means the older son does 16/60 of the job in 3 hours, which means 16/180 of the job in 1 hour. \n" ); document.write( "So the number of hours the older son alone would need to do the job alone is 180/16 = 11.25 hours. \n" ); document.write( " |