document.write( "Question 1101866: A man can do a job in 10 hours and his younger son can do it in 12 hours. After the father and his younger son have been working for 1 hour, the older son joins them, and the three completed the job in 3 more hours. How long will it take the older son to do the job?
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Algebra.Com's Answer #716484 by josmiceli(19441)\"\" \"About 
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Man's rate is:
\n" ); document.write( "[ 1 job ] / [ 10 hrs ]
\n" ); document.write( "Younger son's rate is:
\n" ); document.write( "[ 1 job ] / [ 12 hrs ]
\n" ); document.write( "Let older son's rate =
\n" ); document.write( "[ 1 job ] / [ t hrs ]
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\n" ); document.write( "Let \"+x+\" = the fraction of the
\n" ); document.write( "job man and younger son get done
\n" ); document.write( "in 1 hr
\n" ); document.write( "Add their rates to get rate working together
\n" ); document.write( "\"+1%2F10+%2B+1%2F12+=+x%2F1+\"
\n" ); document.write( "Multiply both sides by \"+60+\"
\n" ); document.write( "\"+6+%2B+5+=+60x+\"
\n" ); document.write( "\"+60x+=+11+\"
\n" ); document.write( "\"+x+=+11%2F60+\" is the fraction that gets done.
\n" ); document.write( "There is \"+49%2F60+\" of the job left to do
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\n" ); document.write( "\"+1%2F10+%2B+1%2F12+%2B+1%2Ft+=+%28%28+49%2F60+%29%29%2F3+\"
\n" ); document.write( "\"+1%2F10+%2B+1%2F12+%2B+1%2Ft+=+49%2F180+\"
\n" ); document.write( "Multiply both sides by \"+180t+\"
\n" ); document.write( "\"+18t+%2B+15t+%2B+180+=+49t+\"
\n" ); document.write( "\"+33t+%2B+180+=+49t+\"
\n" ); document.write( "\"+16t+=+180+\"
\n" ); document.write( "\"+t+=+11.25+\"
\n" ); document.write( "Working alone, the older son
\n" ); document.write( "can do the job is 11 hrs 15 min
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\n" ); document.write( "Get another opinion if needed\r
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