document.write( "Question 1101845: a man borrows 9000 to buy a house at 9% per yr compound.
\n" ); document.write( "he repaid 920 at the end of each year.
\n" ); document.write( "how much does he still owe at the end of 3 years? \n" ); document.write( "
Algebra.Com's Answer #716458 by Theo(13342)\"\" \"About 
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he borrows 9000 at the beginning of the first year.\r
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\n" ); document.write( "\n" ); document.write( "at the end of the first year, his remaining balance is 9000 * 1.09 - 920 = 8890.\r
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\n" ); document.write( "\n" ); document.write( "at the end of the second year, his remaining balance is 8890 * 1.09 - 920 = 8770.1.\r
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\n" ); document.write( "\n" ); document.write( "at the end of the third year, his remaining balance is 8770.1 * 1.09 - 920 = 8639.409\r
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\n" ); document.write( "\n" ); document.write( "the loan is paid off between 24 years and 25 years.\r
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\n" ); document.write( "\n" ); document.write( "the remaining balance for the 25 years is shown below.\r
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